## Algebra 2 (1st Edition)

$$p=\pm 3\sqrt{3} -1$$
We first try to get the variable squared alone on onside of the equation. Then, we take the square root in order to solve: $$(p+1)^2 = 27 \\ p+1 =\pm\sqrt{27} \\ p = \pm 3\sqrt{3} -1$$