#### Answer

One real solution

#### Work Step by Step

We know that the discriminant is in the form $b^2-4ac$. If this is positive, there are two real solutions. If this is 0, there is one real solution. If this is negative, there are two imaginary solutions. Thus, we find:
$$(10)^2-4(-5)(-5)=0$$
Thus, there is one real solution.