Answer
$\frac{-34}{89}+\frac{1}{89}i$
Work Step by Step
$\frac{3-2i}{-8+5i}=\frac{(3-2i)(-8-5i)}{(-8+5i)(-8-5i)}=\frac{-24-10+16i-15i}{64+25}=\frac{-34+i}{89}=\frac{-34}{89}+\frac{1}{89}i$
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