#### Answer

$\frac{-34}{89}+\frac{1}{89}i$

#### Work Step by Step

$\frac{3-2i}{-8+5i}=\frac{(3-2i)(-8-5i)}{(-8+5i)(-8-5i)}=\frac{-24-10+16i-15i}{64+25}=\frac{-34+i}{89}=\frac{-34}{89}+\frac{1}{89}i$

Published by
McDougal Littell

ISBN 10:
0618595414

ISBN 13:
978-0-61859-541-9

$\frac{-34}{89}+\frac{1}{89}i$

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