## Algebra 2 (1st Edition)

The solutions are $-6$ and $6$.
$3x^{2}+13=121\qquad$ ...add $-13$ to each side. $3x^{2}+13-13=121-13$ $3x^{2}=108\qquad$ ...divide both sides with $3$. $x^{2}=36\qquad$ ...take square roots of each side. $x=\pm\sqrt{36}\qquad$ ...evaluate $\sqrt{36}$ $x=\pm 6$