## Algebra 2 (1st Edition)

The solutions are $x=4$ or $x=-\displaystyle \frac{8}{3}.$
$|-2+3x|=10\qquad$....write equivalent equations. $-2+3x=10$ or $-2+3x=-10\qquad$....solve each equation separately. $-2+3x=10\qquad$ ...add $2$ to each side. $-2+3x+2=10+2\qquad$ ...simplify. $3x=12\qquad$ ...divide each side with $3$. $x=4$ $-2+3x=-10\qquad$ ...add $2$ to each side. $-2+3x+2=-10+2\qquad$ ...simplify. $3x=-8\qquad$ ...divide each side with $3$. $x=-\displaystyle \frac{8}{3}$