## Algebra 2 (1st Edition)

$x=-4, -5$
Solve the equation: $x^{2}+9x+20=0$ $x^{2}+5x+4x+20=0$ $x(x+5)+4(x+5)=0$ $(x+4)(x+5)=0$ Because of the Zero Product Property, $(x+4)=0$ and $(x+5)=0$ are both true. Therefore, $x=-4, -5$