Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.4 Solve ax(squared) + bx + c = 0 by Factoring - 4.4 Exercises - Quiz for Lessons 4-1-4.4 - Page 265: 7


$x=-4, -5$

Work Step by Step

Solve the equation: $x^{2}+9x+20=0$ $x^{2}+5x+4x+20=0$ $x(x+5)+4(x+5)=0$ $(x+4)(x+5)=0$ Because of the Zero Product Property, $(x+4)=0$ and $(x+5)=0$ are both true. Therefore, $x=-4, -5$
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