Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.4 Solve ax(squared) + bx + c = 0 by Factoring - 4.4 Exercises - Problem Solving - Page 264: 63


$2$ ft

Work Step by Step

Our equation according to the exercise: $(12+2x)(8+2x)-12\cdot8=12\cdot8\\96+16x+24x+4x^2-96=96\\4x^2+40x-96=0\\x^2+10x-24=0\\(x+12)(x-2)=0$ Thus $x=-12$ or $x=2$, but $x$ has to positive, thus $x=2$.
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