Answer
$(b-5)(b+8)$
Work Step by Step
We try to find factors of c in $x^2+bx+c$ that add to negative b,
In this case...
$b^2+8b-5b-40$
$b(b+8)-5(b+8)$
$(b-5)(b+8)$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 4 Quadratic Functions and Factoring - 4.3 Solve x(squared) + bx + c = 0 - 4.3 Exercises - Skill Practice - Page 255: 9
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