Answer
$45$ and $28$
Work Step by Step
Our equation is: $2\cdot35\cdot18=(35+x)(18+x)\\1260=630+x^2+53x\\x^2+53x-630=0\\(x+63)(x-10)=0$
Thus $x=10$ or $x=−63$ but $x$ has to be positive, thus $x=10$.
Thus, the new dimensions are $45$ and $28$.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 4 Quadratic Functions and Factoring - 4.3 Solve x(squared) + bx + c = 0 - 4.3 Exercises - Problem Solving - Page 257: 66
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