## Algebra 2 (1st Edition)

Published by McDougal Littell

# Chapter 4 Quadratic Functions and Factoring - 4.3 Solve x(squared) + bx + c = 0 - 4.3 Exercises - Problem Solving - Page 257: 66

#### Answer

$45$ and $28$

#### Work Step by Step

Our equation is: $2\cdot35\cdot18=(35+x)(18+x)\\1260=630+x^2+53x\\x^2+53x-630=0\\(x+63)(x-10)=0$ Thus $x=10$ or $x=−63$ but $x$ has to be positive, thus $x=10$. Thus, the new dimensions are $45$ and $28$.

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