Chapter 4 Quadratic Functions and Factoring - 4.10 Write Quadratic Functions and Models - 4.10 Exercises - Skill Practice - Page 312: 17

$y=-(x+2)(x-3)$

We already know $y$, $x$, $p$ and $q$ from the given x-intercepts and the point, so in order to get the quadratic function we need to find $a$... $y=a(x-p)(x-q)$ $6=a(2)a(-3)$ $6=-6a$ $a=-\frac{6}{6}$ $a=-1$ Therefore the function is... $y=-(x+2)(x-3)$