Answer
See below
Work Step by Step
The equation from part (a),
$y=0.0119x^2-0.3086x-0.000476$
Substitute $x=10$:
$y=0.0119(10)^2-0.3086(10)-0.000476\\
\approx -1.896$ sec
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 4 Quadratic Functions and Factoring - 4.10 Write Quadratic Functions and Models - 4.10 Exercises - Problem Solving - Page 314: 49b
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