Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.10 Write Quadratic Functions and Models - 4.10 Exercises - Mixed Review - Page 315: 60

Answer

See below

Work Step by Step

Given: $3x+7y=1\\4x+5y=23$ Multiply the second equation by $-4$: $-12x-28y=-4$ Multiply the second equation by $-3$ $12x+15y=69$ Then we have $-13y=65\\ \rightarrow y=-5$ Substitute: $3x+7(-5)=1\\ \rightarrow 3x=36\\ \rightarrow x=12$
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