## Algebra 2 (1st Edition)

The function has a minimum, and the value of the minimum is $y=7$
The function is a square function, and the $a$-value is positive, so the function must open upwards, meaning that it has a minimum. Since there is no horizontal shift on the function, the $x$-coordinate of the minimum will be zero, just like the parent function. Therefore, we can substitute $0$ for $x$, and evaluate for the value of $y$. Doing this results in: $y=9\times0^{2}+7=9\times0+7=0+7=7$ The minimum of the function is $y=7$.