Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.1 Quadratic Functions in Standard Form - 4.1 Exercises - Skill Practice - Page 241: 34


The function has a minimum, and the value of the minimum is $y=7$

Work Step by Step

The function is a square function, and the $a$-value is positive, so the function must open upwards, meaning that it has a minimum. Since there is no horizontal shift on the function, the $x$-coordinate of the minimum will be zero, just like the parent function. Therefore, we can substitute $0$ for $x$, and evaluate for the value of $y$. Doing this results in: $y=9\times0^{2}+7=9\times0+7=0+7=7$ The minimum of the function is $y=7$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.