Answer
The graph is attached.
Work Step by Step
We know that parabolas follow the form $y=ax^2+bx+c$. Thus, once the parabola is in this form, we can graph it. After all, we know that $-\frac{b}{2a}$ is the vertex, and c is the y-intercept. Also, if a is positive, the graph opens up, while if a is negative, the graph opens down. Knowing this, we create the graph. Recall, if there is ever any difficulty with graphing, one can always create a table of values and plot those points to see the shape of the curve.
As the problem requests, the graph of $y=x^2$ is included for reference.
![](https://gradesaver.s3.amazonaws.com/uploads/solution/f337138f-544e-4fec-8f4e-2cf4c0b19a64/steps_image/small_1561050909.jpg?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Credential=AKIAJVAXHCSURVZEX5QQ%2F20240727%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Date=20240727T014107Z&X-Amz-Expires=900&X-Amz-SignedHeaders=host&X-Amz-Signature=5036d46ac24e61d18412e18d0f17fecc42c2cc24cce16f2810c02e571ebcd189)