Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - Mixed Review of Problem Solving - Lessons 3.5-3.8 - Page 220: 1c

Answer

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Work Step by Step

We have: $A=\begin{bmatrix} 4.5 & 6 & 2.5\\ 5.5 & 8 & 2.5 \end{bmatrix}$ $B=\begin{bmatrix} 4 & 6.5 & 3.25\\ 5 & 8.5 & 3.25 \end{bmatrix}$ To make each cost 10% higher: $1.1A=1.1\begin{bmatrix} 4.5 & 6 & 2.5\\ 5.5 & 8 & 2.5 \end{bmatrix}=\begin{bmatrix} 4.95 & 6.6 & 2.75\\ 6.05 & 8.8 & 2.75 \end{bmatrix}$ $1.1B=1.1\begin{bmatrix} 4 & 6.5 & 3.25\\ 5 & 8.5 & 3.25 \end{bmatrix}=\begin{bmatrix} 4.4 & 7.15 & 3.58\\ 5.5 & 9.35 & 3.58 \end{bmatrix}$
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