Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - Investigating Algebra Activity - 2.1 Solving Linear Systems Using Tables - Page 152: 6

Answer

The system has no solution

Work Step by Step

We first have to solve the equations for $y$. $x+y=11$ Simplify $y=-x+11$ $-x-y=11$ Simplify $y=-x-11$ To solve the equation, we will use the table function of a graphing calculator. Input both of the equations as $y_1$ and $y_2$ and look for an $x$ value where both $y_1$ and $y_2$ are the same. $y_1=-x+11$ $y_2=-x-11$ As the output shows, this system has no solution.
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