Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - Chapter Review - Page 225: 27

Answer

$$\begin{pmatrix}-2&6&-15\\ 6&0&-3\end{pmatrix}$$

Work Step by Step

Finding the product of the matrices, we obtain: $$\begin{pmatrix}\left(-2\right)\cdot \:6+5\cdot \:2&\left(-2\right)\left(-3\right)+5\cdot \:0&\left(-2\right)\cdot \:5+5\left(-1\right)\\ 0\cdot \:6+3\cdot \:2&0\cdot \left(-3\right)+3\cdot \:0&0\cdot \:5+3\left(-1\right)\end{pmatrix} \\ \begin{pmatrix}-2&6&-15\\ 6&0&-3\end{pmatrix}$$
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