Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.5 Perform Basic Matrix Operations - Guided Practice for Examples 3 and 4 - Page 190: 6

Answer

$x=5,y=6$

Work Step by Step

$-2\left(\begin{bmatrix} -3x&-1\\ 4&y \end{bmatrix}+\begin{bmatrix} 9&-4\\ -5&3 \end{bmatrix}\right)=\begin{bmatrix} 12&10\\ 2&-18 \end{bmatrix}\\-2\left(\begin{bmatrix} -3x+9&-5\\ -1&3+y \end{bmatrix}\right)=\begin{bmatrix} 12&10\\ 2&-18 \end{bmatrix}\\\begin{bmatrix} 6x-18&10\\ 2&-6-2y \end{bmatrix}=\begin{bmatrix} 12&10\\ 2&-18 \end{bmatrix}$ Then we can see that $6x-18=12\\6x=30\\x=5$ and $-6-2y=-18\\-2y=-12\\y=6$
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