Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.4 Solve Systems of Linear Equations in Three Variables - Guided Practice for Examples 1, 2, and 3 - Page 180: 1

Answer

$$z=-2,\:y=3,\:x=1$$

Work Step by Step

To solve, we first must isolate one of the variables to solve for that variable. Then, we use that value to solve for the other two variables: $$\frac{10-\left(-\frac{-5z-22}{4}\right)+2z}{3}+4\left(-\frac{-5z-22}{4}\right)+3z=7 \\ z=-2$$ Thus: $$y=-\frac{-5\left(-2\right)-22}{4}=3$$ $$x=\frac{10-3+2\left(-2\right)}{3}=1$$
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