Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.4 Solve Systems of Linear Equations in Three Variables - 3.4 Exercises - Problem Solving - Page 185: 47a


$r+l+i=12$ $2.5r+4l+2i=32$ $r=2(l+i)$

Work Step by Step

Let r = the number of roses l = the number of lilies i= the number of irises She has a budget of $\$160$ and wants 12 flowers for each bouquet. Roses cost $\$2.50$ each, lilies cost $\$4$ each, and irises cost $\$2$ each. $r+l+i=12$ $5(2.5r+4l+2i)=160$ She wants twice as many roses as the other two types of flowers combined: $r=2(l+i)$ Hence, we have the system of equations: $r+l+i=12$ $5(2.5r+4l+2i)=160$ $r=2(l+i)$ Simplify: $r+l+i=12$ $2.5r+4l+2i=32$ $r=2(l+i)$
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