Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.2 Solve Linear Systems Algebraically - 3.2 Exercises - Skill Practice - Page 164: 38



Work Step by Step

Solving the equation using substitution, we find: $$3\cdot \frac{-12-5y}{7}-4y=1 \\ y=-1$$ Thus: $$x=\frac{-12-5\left(-1\right)}{7}=-1$$
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