Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.2 Solve Linear Systems Algebraically - 3.2 Exercises - Skill Practice - Page 164: 17

Answer

$x=-6$ and $y=-2$

Work Step by Step

$3x-4y=-10$ $/\times(-2)$ to get rid of the $x$ $6x+3y=-42$ _________________ $-6x+8y=20$ $6x+3y=-42$ _________________ $11y=-22$ $y=\frac{-22}{11}$ $y=-2$ when $y=-2$... $3x-4(-2)=-10$ $3x+8=-10$ $3x=-18$ $x=-6$
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