Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.1 Solve Linear Systems by Graphing - 3.1 Exercises - Mixed Review - Page 158: 52


$y=\frac{4}{3}x-\frac{20}{3}$ when $x=-7$ then $y=-16$

Work Step by Step

$-12x+9y=-60$ $9y=12x-60$ $y=\frac{12}{9}x-\frac{60}{9}=\frac{4}{3}x-\frac{20}{3}$ when $x=-7$ $y=\frac{4}{3}\times(-7)-\frac{20}{3}=-\frac{28}{3}-\frac{20}{3}=-\frac{48}{3}$ $y=-16$
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