Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.1 Solve Linear Systems by Graphing - 3.1 Exercises - Mixed Review - Page 158: 51


$y=-\frac{16}{9}x-\frac{8}{3}$ when $x=-6$ then $y=8$

Work Step by Step

$16x+9y=-24$ $9y=-16x-24$ $y=-\frac{16}{9}x-\frac{24}{9}=-\frac{16}{9}-\frac{8}{3}$ when $x=-6$ $y=-\frac{16}{9}\times(-6)-\frac{8}{3}=\frac{32}{3}-\frac{8}{3}=\frac{24}{3}$ $y=8$
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