## Algebra 2 (1st Edition)

The student multiplied y and x instead of dividing the two quantities. However, the value of $\frac{y}{x}$ for the first term is $\frac{24}{1}$, but the value for the second term in $\frac{8}{3}$. But, with direct variation, $\underline{all}$ data points have the same value of $\frac{y}{x}$. Hence, this is not direct variation.