## Algebra 2 (1st Edition)

$$y-.9=-1.25(x-.6)$$
We first find the slope: $$m=\frac{-2.6-0.9}{3.4-0.6}=-1.25$$ We know that point slope form is expressed as $y-y_1=m(x-x_1)$, where $(x_1,y_1)$ is a point on the line, and m is the slope of the line. Using this, we find that the equation of the line is: $$y-.9=-1.25(x-.6)$$