Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 14 Trigonometric Graphs, Identities, and Equations - Chapter Review - Page 968: 28



Work Step by Step

Using the given formula and the known values: $\sin(\frac{13\pi}{12})=\sin(\frac{\pi}{3})\cos(\frac{3\pi}{4})+\sin(\frac{3\pi}{4})\cos(\frac{\pi}{3})=\frac{\sqrt3}{2}(-\frac{1}{\sqrt2})+\frac{1}{\sqrt2}\frac{1}{2}=-\frac{\sqrt3-1}{2\sqrt2}$
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