## Algebra 2 (1st Edition)

Published by McDougal Littell

# Chapter 14 Trigonometric Graphs, Identities, and Equations - Chapter Review - Page 966: 19

See below.

#### Work Step by Step

$\frac{\sin^2 (-x)-1}{\cot^2 x}=\frac{\sin^2 x-1}{\frac{\cos^2 x}{\sin ^2 x}}=\frac{-\cos^2 x}{\frac{\cos^2 x}{\sin ^2 x}}=-\sin ^2 x$ Hence we proved what we had to.

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