## Algebra 2 (1st Edition)

$\cos\theta-\sin\theta$
Using the given formula and the known values: $\frac{\cos(2\theta)}{\sin\theta+\cos\theta}=\frac{\cos^2\theta-\sin^2\theta}{\sin\theta+\cos\theta}=\frac{(\sin\theta+\cos\theta)(\cos\theta-\sin\theta)}{\sin\theta+\cos\theta}=\cos\theta-\sin\theta$