## Algebra 2 (1st Edition)

$$x=\frac{\pi }{3}+2\pi n,\:x=\frac{2\pi }{3}+2\pi n$$
Solving for a general solution to the equation, we find: $$\sin \left(x\right)=\frac{\sqrt{3}}{2} \\ x=\frac{\pi }{3}+2\pi n,\:x=\frac{2\pi }{3}+2\pi n$$