Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 14 Trigonometric Graphs, Identities, and Equations - 14.6 Apply Sum and Difference Formulas - 14.6 Exercises - Problem Solving - Page 954: 43b


See below.

Work Step by Step

Plugging in $t=0$ into the simplified formula $\frac{f\frac{\tan\theta-\tan t}{1+\tan\theta\tan t}+f\tan t}{h\tan\theta}$ we get: $\frac{f\frac{\tan\theta-\tan (0)}{1+\tan\theta\tan (0)}+f\tan (0)}{h\tan\theta}=\frac{f\frac{\tan\theta-0}{1+\tan\theta(0)}+f(0)}{h\tan\theta}=\frac{f\frac{\tan\theta}{1}}{h\tan\theta}=\frac{f}{h}$ Hence we proved what we had to.
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