## Algebra 2 (1st Edition)

$$x=2\pi n,\:x=\frac{2\pi }{3}+2\pi n$$
We solve the equation using the properties of trigonometric functions. Note, there is a general solution since trigonometric identities go up and down and this can pass through a given value of y many times. Solving this, we find: $$\left(1-\cos \left(x\right)\right)^2=\left(\sqrt{3}\sin \left(x\right)\right)^2 \\ \left(1-\cos \left(x\right)\right)^2-3\sin ^2\left(x\right)=0 \\ \left(1-\cos \left(x\right)\right)^2-\left(1-\cos ^2\left(x\right)\right)\cdot \:3=0 \\ \cos \left(x\right)=1,\:\cos \left(x\right)=-\frac{1}{2} \\ x=2\pi n,\:x=\frac{2\pi }{3}+2\pi n$$