Answer
$$\frac{1}{2-3x^2}$$
Work Step by Step
Simplifying the expression by trying to cancel terms that are in the numerator and the denominator, we find:
$$\frac{8x^2}{16x^2-24x^4} \\ \frac{8x^2}{8x^2\left(2-3x^2\right)} \\ \frac{1}{2-3x^2}$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 14 Trigonometric Graphs, Identities, and Equations - 14.2 Translate and Reflect Trigonometric Graphs - 14.2 Exercises - Mixed Review - Page 922: 56
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