## Algebra 2 (1st Edition)

$x=\sqrt {e^{25}/9}$ or $x=\sqrt {e^{25}}/3$
Moving all of the constants to one side gives us, $25=2*\ln(3x)$ Thus $25=ln(9x^2)$, by log properties. So, $e^{25}=9x^2$ Thus, $x=\sqrt {e^{25}/9}$