## Algebra 2 (1st Edition)

$60^{\circ}$
Let the $a$ be the radius of the circle of the latitude. Here, $\cos \theta =\dfrac{a}{r} \implies a=r \cos \theta$ Thus, we have $2 \pi r =\pi r \implies r=2a$ Now, $2 r \cos \theta=r$ This gives: $\cos \theta=\dfrac{1}{2}$ Thus, $\theta=60^{\circ}$