## Algebra 2 (1st Edition)

$16.5 ft/s$
Here, we have $\theta=18^{\circ}$ and $d=5$ We know that $d=\dfrac{v^2}{32} \sin (2 \theta)$ $5=\dfrac{v^2}{32} \sin 2 (18^{\circ})$ This implies that $v^2=272.21$ Thus, $v= \sqrt {272.21}=16.5 ft/s$