Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.2 Define General Angles and Use Radian Measure - 13.2 Exercises - Mixed Review - Page 865: 58

Answer

$$6\sqrt{5}$$

Work Step by Step

Simplifying the radical using the rules of radicals, we find: $$\sqrt{5}\sqrt{2^2}\sqrt{3^2} \\ 2\cdot \:3\sqrt{5} \\ 6\sqrt{5}$$
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