Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.1 Use Trigonometry with Right Triangles - Guided Practice for Examples 1 and 2 - Page 853: 4

Answer

$\dfrac{\sqrt{51}}{10}$

Work Step by Step

$\textbf{Step 1}$ We draw a right triangle with acute angle $\theta$ such that the leg adjacent $\theta$ has length $7$ and the hypotenuse has length $10$. The length of $x$ (the leg opposite $\theta$) can be calculated using the Pythagorean theorem: $$x=\sqrt{10^2-7^2}=\sqrt{51}.$$ $\textbf{Step 2}$ Calculate $\sin\theta$: $$\sin\theta=\dfrac{opp}{hyp}=\dfrac{\sqrt{51}}{10}.$$
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