Answer
See below
Work Step by Step
Let's suppose $r=0.5$, then we have: $$\frac{a_1}{1-r}=4\\\frac{a_1}{1-0.5}=4\\a_1=2$$
Hence, $\sum^{\infty}_{n=0} a_1\times^n=\sum^{\infty}_{n=0} 2\times0.5^n$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - Mixed Review of Problem Solving - Lessons 12.4-12.5 - Page 838: 9
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