Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.5 Use Recursive Rules with Sequences and Functions - Guided Practice for Examples 1 and 2 - Page 828: 7

Answer

$\left\{\begin{array}{l} a_{1}=11\\ a_{n}=a_{n-1}+11 \end{array}\right.$

Work Step by Step

Note the common difference between consecutive terms ($d=11$). This is an arithmetic sequence, for which we have $a_{n}=a_{n-1}+d,$ In this case, $a_{n}=a_{n-1}+11.$ For a recursive rule, we give the information about the first term, and a rule on how to obtain the next term from the preceding: $\left\{\begin{array}{l} a_{1}=11\\ a_{n}=a_{n-1}+11 \end{array}\right.$
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