## Algebra 2 (1st Edition)

$1,4,7,10,13$
In order to compute the fifth term we will have to plug $n =1,2,3,4,5$ into the given equation. Now, we have $a_2= a_1+3 = 1+3=4$; $a_3= 4+3=7$; $a_4= 7+3=10$; $a_5= 10+3=13$; Thus, we have the terms $1,4,7,10,13$