Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.4 Find Sums of Infinite Geometric Series - 12.4 Exercises - Mixed Review - Page 825: 48

Answer

$a_n=216-18n$

Work Step by Step

Here, we have $a_n= a_1+d(n-1)$ for the Arithmetic series. The common difference between the successive terms is $d=-18$ First term is: $a_8=72$ Here, we have $a_8= a_1+7d$ and $a_1=a_8-7d=72-7 \times (-18)=198$ $a_n=198+(-18) \times (n-1)=198-18n+18$ Hence, $a_n=216-18n$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.