Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.3 Analyze Geometric Sequences and Series - 12.3 Exercises - Problem Solving - Page 815: 57a

Answer

$a_n=5(2)^{n-1}$

Work Step by Step

The nth term is given by $a_n= a_1 r^{n-1}$ ...(1) Here, we have Common Ratio $r=2$ and first term $a_1=5$ Equation (1) gives: $a_n=5 \times (2)^{n-1}$ Hence, $a_n=5(2)^{n-1}$
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