Answer
13
Work Step by Step
Solving for x using the rules of exponents, we find:
$$7^{x-3}=\left(7^2\right)^{x-8} \\ 7^{x-3}=7^{2\left(x-8\right)} \\ x-3=2\left(x-8\right) \\ x=13$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - 12.2 Analyze Arithmetic Sequences and Series - 12.2 Exercises - Mixed Review - Page 809: 80
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