Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.2 Analyze Arithmetic Sequences and Series - 12.2 Exercises - Mixed Review - Page 809: 80



Work Step by Step

Solving for x using the rules of exponents, we find: $$7^{x-3}=\left(7^2\right)^{x-8} \\ 7^{x-3}=7^{2\left(x-8\right)} \\ x-3=2\left(x-8\right) \\ x=13$$
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