Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - 12.1 Define and Use Sequences and Series - Guided Practice for Examples 5 and 6 - Page 797: 11



Work Step by Step

$\displaystyle \sum_{k=3}^{7}(k^{2}-1)=(3^{2}-1)+(4^{2}-1)+(5^{2}-1)+(6^{2}-1)+(7^{2}-1)$ $=8+15+24+35+48$ $=130$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.