## Algebra 2 (1st Edition)

$\qquad \displaystyle \sum_{n=1}^{\infty}6^{n}$
From the first four terms, we observe the pattern nth term = $6^{n}$. The first term corresponds to n=1 (lower limit). The sum has infinitely many terms (no upper limit ... we write $\infty$) Summation notation:$\qquad \displaystyle \sum_{n=1}^{\infty}6^{n}$