Answer
See below
Work Step by Step
The standard deviation of $x_1,x_2,...,x_n$ is (where $\overline{x}$ is the mean of the data values): $\sqrt{\frac{(x_1-\overline{x})^2+(x_2-\overline{x})^2+...+(x_n-\overline{x})^2}{n}}$
The standard deviation is: $\sqrt{\frac{(94- \bar x)^2+(109-\bar x)^2+...+(101-\bar x)^2}{n}}\approx 21.176$
