Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - Chapter Review - Page 785: 14

Answer

$0.4837$

Work Step by Step

$\text{z-score}=\frac{\text{data item-mean}}{\text{standard deviation}}$ Hence here the z-score is: $\frac{91-95}{7}\approx-0.6,\frac{100-95}{7}\approx0.7$ Then, using the table: $P(91\leq x\leq 100)=P(-0.6\leq z\leq 0.7)=P(z\leq0.7)-P(z\leq-0.6)\approx0.7580-0.2743=0.4837$
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