Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - Chapter Review - Page 784: 8

Answer

See below.

Work Step by Step

The mean of $n$ numbers is the sum of the numbers divided by $n$. The median of $n$ is the middle number of the numbers when they are in order (and the mean of the middle $2$ numbers if $n$ is even). The mode of $n$ numbers is the number or numbers that appear(s) most frequently. Hence here the mean is: $\frac{0.97+1.04+1.13+1.13+ 1.13+ 1.14+1.26+ 1.30+ 1.47+ 1.47+ 1.59}{11}=1.239$. The median is the middle item in the sequence $0.97,1.04, 1.13, 1.13, 1.13, 1.14,1.26, 1.30, 1.47, 1.47, 1.59$, which is: $\$1.14$. The range is the difference between the largest and the smallest data value. The standard deviation of $x_1,x_2,...,x_n$ is (where $\overline{x}$ is the mean of the data values): $\sqrt{\frac{(x_1-\overline{x})^2+(x_2-\overline{x})^2+...+(x_n-\overline{x})^2}{n-1}}$. Hence here the standard deviation is: $\sqrt{\frac{(0.97-1.239)^2+(104-1.239)^2+...+(1.59-1.239)^2}{11-1}}\approx0.198$
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