Answer
See below
Work Step by Step
Given: $y=\frac{1}{4}(x-3)^2+2$
We can see that $a=\frac{1}{4}\\h=3\\k=2$
The vertex is: $(h,k)=(3,2)$
Find some points
$x=0\rightarrow y=4.25\\x=6 \rightarrow y=4.25$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 11 Data Analysis and Statistics - 11.4 Select and Draw Conclusions from Samples - 11.4 Exercises - Mixed Review - Page 771: 35
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